Update questions.

maths/assignment-matrices/assign.tex

@@ -9,20 +9,26 @@
 \date{05 May, 2020}
 \maketitle
 \section{Question 1}
-\[
-	A =
-	\begin{bmatrix}
-		2 & -5 & -1 \\
-		-2 & -1 & 4
-	\end{bmatrix}
-	B =
-	\begin{bmatrix}
-		3 & 4 & 0 \\
-		5 & -2 & 3
-	\end{bmatrix}
-\]
+If
+\(
+A =
+\begin{bmatrix}
+	2 & -5 & -1 \\
+	-2 & -1 & 4
+\end{bmatrix}
+B =
+\begin{bmatrix}
+	3 & 4 & 0 \\
+	5 & -2 & 3
+\end{bmatrix}
+\) find:
 
-\subsection{Part i}
+\begin{enumerate}
+	\item $A + B$
+	\item $2A + B$
+\end{enumerate}
+
+\subsection{Part 1}
 \[
 	A + B =
 	\begin{bmatrix}
@@ -37,7 +43,7 @@
 		3 & -3 & 7
 	\end{bmatrix}
 \]
-\subsection{Part ii}
+\subsection{Part 2}
 \[
 	2A + B =
 	\begin{bmatrix}
@@ -55,20 +61,20 @@
 
 
 \section{Question 2}
-\[
-	A =
-	\begin{bmatrix}
-		1 & 2 & 3 \\
-		4 & 5 & 6 \\
-		7 & 8 & 9
-	\end{bmatrix}
-	B =
-	\begin{bmatrix}
-		1 & 0 & 2 \\
-		2 & 1 & 2 \\
-		5 & 2 & 3
-	\end{bmatrix}
-\]
+If \(
+A =
+\begin{bmatrix}
+	1 & 2 & 3 \\
+	4 & 5 & 6 \\
+	7 & 8 & 9
+\end{bmatrix}
+B =
+\begin{bmatrix}
+	1 & 0 & 2 \\
+	2 & 1 & 2 \\
+	5 & 2 & 3
+\end{bmatrix}
+\), find $AB$.
 \[
 	AB =
 	\begin{bmatrix}
@@ -354,13 +360,13 @@ We know that
 		0 & 1 & 0 \\
 		1 & 0 & 0
 	\end{vmatrix}
-	 = 1 \times
-	 \begin{vmatrix}
-		 0 & 1 \\
-		 1 & 0
-	 \end{vmatrix}
-	 = 1 \times -1 = -1
- \]
+	= 1 \times
+	\begin{vmatrix}
+		0 & 1 \\
+		1 & 0
+	\end{vmatrix}
+	= 1 \times -1 = -1
+\]
 
 \[
 	A^{-1} = \frac{adj.A}{|A|}